How Does Uranium-238 Capture Neutrons and What Happens After?

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SUMMARY

Uranium-238 captures neutrons through a resonant process at approximately 7 eV, which is crucial for moderating neutrons to thermal speeds. When a neutron is absorbed, a gamma photon is typically emitted, representing the binding energy required to stabilize the new nucleus. The resulting nucleus may be stable or unstable, depending on its energy levels and decay pathways. The energy of the absorbed neutron directly influences the emitted gamma energy, with each nucleus exhibiting a unique spectrum of capture gammas.

PREREQUISITES
  • Understanding of neutron capture processes in nuclear physics
  • Familiarity with gamma radiation and its significance in nuclear reactions
  • Knowledge of energy levels and excited states in atomic nuclei
  • Basic principles of neutron moderation and fission reactions
NEXT STEPS
  • Research "Uranium-238 neutron capture cross-section" for detailed insights on resonance absorption
  • Study "Gamma spectroscopy techniques" to analyze emitted gamma rays from nuclear reactions
  • Explore "Nuclear decay pathways" to understand stability and decay of isotopes
  • Investigate "Neutron moderation methods" to enhance fission efficiency in reactors
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Nuclear physicists, nuclear engineers, and students studying nuclear reactions and radiation physics will benefit from this discussion.

wdlang
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can anyone give an example in which a nucleus absorbs a neutron and becomes a stable nucleus?

or the combination must break into parts?
 
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H + n --> D + gamma
 
Vanadium 50 said:
H + n --> D + gamma

in this case, a gamma photon is emitted

is it possible that no particle is emitted at all?

just A+B ----> C ?
 
No, because energy-momentum would not be conserved.
 
You would need exactly the energy of the final particle, and you don't get this. For short-living particles, the energy can vary a bit, and it is possible.
 
wdlang said:
can anyone give an example in which a nucleus absorbs a neutron and becomes a stable nucleus?

or the combination must break into parts?
There is usually a prompt gamma released upon a neutron combining with a nucleus. The product nucleus increases it's mass, but by less than the mass of the neutron. The gamma represents the binding energy needed to remove that neutron.

The product nucleus could be stable, i.e., not undergo β-decay or EC.

Some nuclei have very low energy capture gammas (but the product nucleus isn't necessarily stable).
http://www.nndc.bnl.gov/capgam/bye/page01.html

There is also the consideration of the kinetic energy and momentum of the original nucleus and neutron.
 
Uranium 238 is supposed to have resonant capture of neutrons at 7 eV, which is why it is so important to moderate neutrons to thermal speed before uranium 238 captures them.

Does it mean that uranium 239 has an excited state exactly 7 eV above uranium 238?

If uranium 238 absorbs neutrons at, say, 9 or 10 eV, will the nuclei be emitting light rather than gamma rays?
 
snorkack said:
Uranium 238 is supposed to have resonant capture of neutrons at 7 eV, which is why it is so important to moderate neutrons to thermal speed before uranium 238 captures them.
Neutrons are moderated to thermal energies in order to take advantage of the higher fission cross-section of U-235 (or Pu-239) for thermal neutrons. The resonance absorption of neutrons is just a complication in a moderated system. Fission neutrons are born in the MeV range, and must be slowed to < 0.1 eV to take advantage of the high cross-sections in the thermal range.

Does it mean that uranium 239 has an excited state exactly 7 eV above uranium 238?

If uranium 238 absorbs neutrons at, say, 9 or 10 eV, will the nuclei be emitting light rather than gamma rays?
The energy 7 eV or 9 eV has nothing to with the nuclear energy levels within the nucleus, only with the neutron energy. If U-238 absorbs 7 eV or 9 eV neutron, the emitted capture (or prompt) gamma would have the same energy. However, each nuclei has a unique spectrum of capture gammas, meaning that the nucleus has a number of internal excited states, which would be reflected in the subsequent decay of that nucleus.

http://www.nndc.bnl.gov/capgam/byn/page255.html
A list of levels, a level scheme and decay radiation information are available
http://www.nndc.bnl.gov/chart/reCenter.jsp?z=92&n=146

Visible light photon energies are on the order of 1.5-3.5 eV
 
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