How Far Does Superwoman Travel in the First 8 Seconds?

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SUMMARY

Superwoman travels a distance of 200 meters in the first 8 seconds while decelerating from 108 km/h to 36 km/h. The calculation involves determining the area under the velocity-time graph, which consists of a triangle and a rectangle. The correct interpretation of the problem states that the deceleration occurs over the entire 8 seconds, leading to the accurate distance calculation. Misunderstanding the units and the nature of the calculation led to the initial incorrect conclusion of 576 km/h.

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It's an easy question but I am not getting the correct answer as the book states.

Superwoman is flying at 108km/h. She decelerates at a constant rate to 36km/h

How far in meters does super woman travel in the first 8 seconds?

They told me to draw a velocity time graph which I did. I found the area of the first 8 seconds

http://imgur.com/UDBvOZW

ATriangle+ARectangle

=(8*72)/2 + 8*36
=288+288
=576km/h which is 160m/s

But the correct answer is 200...
 
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kencamarador said:
Superwoman is flying at 108km/h. She decelerates at a constant rate to 36km/h
How far in meters does super woman travel in the first 8 seconds?
You seem to have misstated the problem a little. It must have said that she took 8 seconds to decelerate to 36km/h.
=(8*72)/2 + 8*36
Try including units in there and see what happens.
160m/s
That's a speed, not a distance.
 

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