How Far Will a Uniformly Accelerating Train Travel Before Stopping?

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SUMMARY

The discussion focuses on solving a physics problem involving a train with uniform acceleration. The train takes 20 seconds to travel the first 400 meters and 30 seconds for the next 400 meters. To determine how much farther the train will travel before coming to rest, participants suggest using the equations of motion, specifically s = vo*t - 1/2*a*t^2, to derive the initial velocity (vo) and acceleration (a) from the given time intervals and distances.

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Phyzics J
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Can Someone help me with this constant acceleration problem?! pleasez

1. A train which is moving with uniform acceleration is observed to take 20s and 30s, respectively, to travel successive 400m. How much farther will it travel vefore coming to rest if the acceleration remains constant?



2. I tried to find the change in velocity between those time intervals by using the formula:
Velocity=change in displacement/time



The Attempt at a Solution

 
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Hi Phyzics J, welcome to PF.
Let vo be the initial velocity when you start observing the train.
Then use
s = vo*t -1/2*a*t^2 and write two equations. One for s = 400 m and t = 20 sand second for s = 400 + 400 = 800 m and t = 20 + 30 = 50 s.
Solve the two equations to find vo and a and proceed.
 


Thank you sooo much rl.bhat, I appreciate it :)
 

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