How far does the car travel before stopping?

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SUMMARY

The discussion centers on calculating the stopping distance of a car with a mass of 200g, an initial speed of 30 m/s, and a braking force of 10,000N. The correct approach involves using the work-energy principle or kinematic equations. The stopping distance is determined to be 90 meters, which can be derived from the equations of motion: \(\vec{F}=m\vec{a}\) and \(\vec{v}_f^2=\vec{v}_i^2+2\vec{a}\Delta x\). The initial calculations presented were incorrect, leading to confusion regarding the final answer.

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Homework Statement



Car: mass = 200g
Moving at 30 m/s
Braking force of 10000N.
How far does the car travel before stopping?

Homework Equations


W=m x N
w = F (delta x)


The Attempt at a Solution


I found work, (2000)(10000) = 20,000,000
Then rearranged the second equation to get delta x, and got 2000 as my answer. The answer is 90m and I'm not getting it. Any suggestions?
 
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collegegirl said:

Homework Statement



Car: mass = 200g
Moving at 30 m/s
Braking force of 10000N.
How far does the car travel before stopping?

You can go one of two routes:

(1) [tex]\vec{F}=m\vec{a}[/tex] and [tex]\vec{v}_f^2=\vec{v}_i^2+2\vec{a}\Delta x[/tex], or

(2) [tex]\Delta E_k=\vec{W}[/tex], where [tex]\vec{W}=\vec{F}\Delta x[/tex].
 

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