How Fast Does a 80 kg Weight Move After Being Pulled 1.5 m on a Rough Plane?

[Garicup]

Homework Statement

A weight, mass m = 80 kg , is pulled over a rough horizontal plane, mu = 0.15, by a force of magnitude F = 359 N, making an angle of 43 degrees with the plane, away from the plane. Calculate the speed of the weight d= 1.5 m away from its initial position assuming that it started from rest.

Homework Equations

F_f = muF_n

Vf² = Vi² + 2ad

The Attempt at a Solution

The applied force is evaluated in the x direction only (since the object remained on the floor)

therefore : Fapp_x = 359 cos 43 = 262.56N

Fn = mg , therefore
F_f = 0.15(80)(9.8) = 117.6N
sumF_x = 262.56 - 117.6 = 144.96N

which means:::: ma = 144.96N
80a = 144.96
a = 1.812

given Vf² = Vi² + 2ad, and vi = 0 (rest)

then Vf² = 2 (1.812)(1.5)

Vf = 2.33 m/s-------> This is what I've done on the question, I am having doubts though, can anyone please verify / correct anywhere I am wrong? Please and Thank you

 

[JoAuSc]

It seems right to me. Why do you have doubts?