How High Did the Pole Vaulter Jump?

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SUMMARY

The discussion centers on calculating the height achieved by a pole vaulter using the conservation of energy principle. The pole vaulter, weighing 50 kg and running at 9.5 m/s, experiences a loss of 200 J due to friction. By applying the equation K1 + U1 = K2 + U2 + Wf, where K represents kinetic energy, U represents potential energy, and Wf represents work done against friction, participants aim to derive the maximum height reached during the vault.

PREREQUISITES
  • Understanding of kinetic and potential energy concepts
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
  • Knowledge of units of measurement in physics (e.g., Joules, meters)
NEXT STEPS
  • Review the conservation of energy in physics
  • Practice solving problems involving kinetic and potential energy
  • Learn about the effects of friction on energy loss
  • Explore advanced pole vaulting techniques and their physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as coaches and athletes interested in the physics behind pole vaulting techniques.

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Homework Statement



A 50 kg pole vaulter running at 9.5 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar is 1.3 m/s, and 200 J of energy is lost due to the friction in the pole, how high did the vaulter jump?

Homework Equations


K1+U1= K2+U2+Wf


The Attempt at a Solution


1/2mvi^2= 1/2mvf^2+mgh+Wf
 
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Okay it doesn't look like much of an attempt at a solution, haha...

List your parameters first, take it small steps at a time...
Once you've listed what known parameters you have substitute it into your relevant equation as stated at you attempt at a solution. Do that and let's work from there...
 

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