How Is a Nonlinear Equation Linearized in FEM Software?

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Discussion Overview

The discussion focuses on the process of linearizing a nonlinear equation within the context of finite element method (FEM) software. Participants explore the mathematical transformations involved in this linearization, including specific equations and methods used.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents a nonlinear equation, Y = G^(-1) * X + a * X^3, and its linearized form, Y(i+1) = (G^(-1) + a * X(i)^2) * X(i+1).
  • Another participant describes the process of factoring out "X" and converting the equation into a recursive form, suggesting that this allows for the calculation of a sequence of "Y" values based on a starting value.
  • A later reply questions whether the linearization is performed using the first two terms of the Taylor series in an incremental form.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the specific method of linearization, as there are differing interpretations and approaches presented. The discussion remains unresolved regarding the exact process used in the FEM software.

Contextual Notes

The discussion includes assumptions about the nature of the equations and the methods of linearization, which may not be fully articulated. There is also a lack of clarity regarding the definitions of terms used in the equations.

aamirmub
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Hi,

I am trying to understand an example from a FEM software manual. The manual mentions a nonlinear equation http://aamir-pc:2080/v6.9/books/exa/graphics/exa_eqn00137.gif and this equation is linearized to obtain http://aamir-pc:2080/v6.9/books/exa/graphics/exa_eqn00152.gif .[/URL] Can anyone please explain how this has been done?
 
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You need to fix your messages. The two equations don't show up.
 
The nonlinear equation is Y= G^(-1) * X + a * X^3 where G and a are constants. The linearized equation is Y(i+1) = (G^(-1) + a * X(i)^2) * X(i+1) where i and i+1 are superscripts.
 
The first thing done is factor out an "X": Y= (G-1+ aX2)X. The next thing done was convert to a recursive form by treating the separate "X"s as if they were different terms in a sequence: Yi+1= (G-1+ aXi2)Xi+1. Given a starting value, X1, you could then calculate a sequence of "Y"s. If that sequence convertes, then [itex]Y= \lim_{i\to\infty}Y^i[/itex] will satisfy that equation: [itex]\lim_{i\to \infty} Y^i= (G^{-1}+ a(\lim_{i\to\infty}X^i)^2)(\lim_{i\to\infty}X^{i+1})[/itex] and, since "Xi" and "Xi+1" refer to the same sequence they both converge to the same limit, X.
 
Thank you for your reply. Is the linearization carried out using the first two terms of the taylor series in incremental form?
 

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