How Is the Effective Stiffness of an Interatomic Bond Calculated in Iron?

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SUMMARY

The effective stiffness of the interatomic bond in iron can be calculated using the Young's modulus formula, where Y represents the modulus, F is the force applied, A is the cross-sectional area, dL is the change in length, and L is the original length. In this case, with a 151 kg mass causing a 1.03 cm elongation in a 2.0 m long iron rod with a square cross-section of 0.12 cm, the calculation yields a specific stiffness value. The formula used is Y = (F/A)/(dL/L), which simplifies to Y = [(151 kg * 9.8 m/s²)/(0.12e-2 m)²]/[(1.03e-2 m)/2].

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  • Understanding of Young's modulus and its application in material science.
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  • Familiarity with unit conversions, particularly between grams, kilograms, and centimeters.
  • Ability to perform algebraic manipulations to solve equations.
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Homework Statement


One mole of iron has a mass of 56 grams and density of 7.87 g/cm^3. You have a long thin bar of iron, 2.0 m long, with a square cross section, 0.12 cm on a side. You hang the rod vertically and attach a 151 kg mass to the bottom, and you observe that the bar becomes 1.03 cm longer. Calculate the effective stiffness of the interatomic bond, modeled as a "spring":

Homework Equations


Y= (F/A)/(dL/L
Y=ks/d

The Attempt at a Solution


Y=[(151*9.8)/(0.12e-2)2]/[(1.03e-2)/2]
 
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