How Is the Equilibrium Constant Calculated for I2 and I- in KI Solution?

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Discussion Overview

The discussion revolves around calculating the equilibrium constant for the reaction between iodine (I2) and iodide ions (I-) in a potassium iodide (KI) solution. Participants explore the implications of a saturated iodine solution and the effects of adding KI, focusing on the equilibrium established in this context.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states the equilibrium reaction I2(aq) + I-(aq) ⇌ I3-(aq) and provides initial concentrations based on the mass of iodine dissolved in different solutions.
  • Another participant suggests starting with the expression for the equilibrium constant and emphasizes the need to identify given concentrations and those that can be calculated.
  • A claim is made that the equilibrium constant can be expressed as K = [I3-]/[I2][I-], but confusion arises regarding the meaning of the concentration of iodine in the KI solution.
  • Some participants discuss why the KI solution can dissolve more iodine than pure water, attributing this to the presence of KI.
  • One participant calculates the moles of I2 in the KI solution and questions the correctness of their approach, suggesting that all I2 dissolves and converts to I3-.
  • Another participant challenges this by indicating that excess iodine was present and not all of it was dissolved, prompting a discussion about the role of solid iodine in the equilibrium.
  • There is a request for clarification on the concentrations at equilibrium, with one participant expressing confusion about the problem's vagueness.
  • A later reply clarifies that the concentration of free iodine in the KI solution is the same as in pure water, and outlines how to determine the total concentration of iodine and the concentration of I3-.
  • One participant expresses gratitude for the clarification, indicating improved understanding.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and confusion regarding the problem, with some agreeing on the need for clarity in the equilibrium concentrations while others present differing interpretations of the information provided.

Contextual Notes

Participants note the importance of distinguishing between free iodine and iodine in the form of I3-, as well as the role of solid iodine in the equilibrium, which remains a point of contention.

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Homework Statement



A saturated solution of iodine in water contains 0.330g of I2/L. More than this can dissolve in a KI solution because of the following equilibrium-

I2(aq) +I-(aq) ------> I3- (aq) where 2 and 3 are subscripts and - is negative charge

A 0.1M KI solution actually dissolves 12.5g of iodine/L, mmost of which is converted to I3-. Assuming that the concentration of I2 in all saturated solutions is same, calculate the equilibrium constant for the above reaction.

Homework Equations


The Attempt at a Solution



0.33g/L is 0.0013 mole and 12.5g/L is 0.0492 mole
I don't know how to proceed
 
Last edited:
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Start writing expression for equilibrium constant. Then think which concentrations you are given, and which you can calculate from the simple stoichiometry.
 
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K=[I3-]/[I2][I-]

Actually, I did not understand the problem. A saturated solution of Iodine in water is given to us.
What is the meaning of 'A 0.1M KI solution actually dissolves 12.5g of iodine/L'
how does this info help us?
 
Why does the iodides solution contain more iodine than solution in pure water?
 
It is so because KI is added to it.
0.1M KI dissolves 0.0492 mole I2
but we have only 0.0013 mole I2 so all of it dissolves and converts into I3-
moles of KI left = 0.1-0.0013
Is this approach correct?
 
No, there was excess iodine present. It was not dissolved, but it was added as a solid, thus there is much more I3- present.

How much? That's where the mass of dissolved iodine comes handy.
 
excess iodine present in KI solution or saturated solution of Iodine in water?
 
No idea what you are asking about. SOLID iodine. Solutions are in contact with the solid. Concentrations given are for the SOLUTIONS.
 
I would be thankful to you if you write the concentrations at equilibrium as this question is very vague to me.
 
  • #10
Concentration of free iodine is identical with the concentration in pure water. Total concentration of iodine dissolved is sum of free iodine and I3-. Simple subtraction will give you concentration of I3-, then simple stoichiometry will tell you how much I- was left.
 
Last edited by a moderator:
  • #11
Thanks a lot. I understood it clearly now.
 

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