1. The problem statement, all variables and given/known data Without adding any Chromium based compounds, how would you manipulate the above equation to produce more CrO42- ions? Be sure to use chemical equations to show the answer. 2. Relevant equations 2CrO42- (aq) + 2H3O+ <--> Cr2O72-(aq) + 3H2O (l) 3. The attempt at a solution So my initial thought here is that we want the reaction to shift left so we must alter the concentration of one of the products on the right. Since adding more Chromium is "not allowed" then it would have to be the water? If this is correct though, I don't know what the equation would look like because if I add more moles of water won't I have to balance all the other species as well to have a balanced chemical equation? Thanks in advance for all the time and help.