How is the junction area of each diode calculated in this circuit?

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SUMMARY

The junction area of each diode in the specified circuit is calculated to be 0.34 relative to a standard diode with a 0.7V drop at 1mA current. The circuit is designed to achieve a voltage output (Vo) of 3V when the load current (IL) is 0A, with a change of 40mV per 1mA of load current. Given that the saturation current (I(s)) is proportional to the junction area, the saturation current for the four identical diodes is calculated as 2.339 x 10-16 A, while the standard diode's saturation current is 6.19 x 10-16 A. The relative area is determined by dividing these two saturation currents.

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shaiqbashir
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Hi Guys!

My Question is this:

Dsign the circuit of the fig: so that Vo= 3V when IL = 0 A AND Vo changes by 40mV per 1mA of load current. the value of R = 4.8Kilo ohms. find the juction area of each diode (assume all four diodes are identical) relative to a diode with 0.7 V drop at 1mA current. Assume n=1.

The ans of this question is 0.34 but how it has been calculated.

Plz help
Thanks in advance:
 

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since we know that I(s) , i.e. the saturation current is proportonal to the junction area , calculate saturation current for the two cases as follows:
first for the four diodes ,given that they are identical, the voltage drop across each will be 3/4 = .75v, I = 2.5 mA. using eq I = I(s)exp(v/nVt) we get saturation curret for the given diode as 2.339 x 10^(-16).
Similarly for the given standard diode that is one with the voltage drop of .7v and I = 1mA
we get saturation current as 6.19 x 10^(-16).

since we have to find the relative area, simply dividing the above two saturation current would give the answer that is .34
 

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