How Is the Total Potential Energy of a Plummer Mass Distribution Calculated?

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Homework Help Overview

The discussion revolves around calculating the total potential energy of a Plummer mass distribution, focusing on how the answer should relate to the gravitational constant G, mass M, and a characteristic length scale a.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the integration limits for calculating potential energy, questioning whether to integrate from 0 to R or from 0 to infinity. There is also discussion about the implications of the integral's limits on the final expression.

Discussion Status

Some participants have suggested that the integral should be evaluated from 0 to infinity, indicating a potential simplification in the expression for total potential energy. However, there is no explicit consensus on the correctness of the derived expressions or the evaluation of the integral itself.

Contextual Notes

There is mention of a specific integral hint provided in the problem statement, which may influence the approach to solving the integral for potential energy. Additionally, participants express confusion regarding the relationship between the variables involved, particularly the role of R in the integral.

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Homework Statement


Now calculate the total potential energy of the Plummer mass distribution. Hint:
The answer should depend only on G, M, and a



Homework Equations


M(r)=Mr3/(r2+a2)3/2
p(r)=3Ma2/4pie(r2+a2)5/2


The Attempt at a Solution


looking at my notes i find a formula to find total potential energy
U=-4pieG integral from 0 to R M(r)P(r)r dr
What i am confused about is that it says hint answer only depends on G M a, but what about the R from the integral? it also said in the problem that hint integral from o to infinity x4dx/(x2+1)4 = pie/32

so looking at the hint integral, instead of doing integral from 0 to R would I just do it from 0 to infinity? That than would get rid of the R and just have answer of just G M a.
Is this right?
thanks
 
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The total potential energy is from R=0 to R=inf. You need to essentially sum up the potential energy at each distance.
 
o ok thxs
 
sorry I am a little bit confused so, after setting the integral from 0 to infinty, your answer should come out to be

-3M^2Ga(pie/32)?
 
i don't know i didn't do the integral yet ill let you know later when I do it.
 
yep that is the answer but its a^2 not a ... wow that was easy
 

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