How Is the Value of 4⋄ Calculated in This Math Problem?

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SUMMARY

The value of 4⋄ is calculated as the product of all positive odd factors of 3 multiplied by 4, which equals 12. The odd factors of 12 are 1 and 3. Therefore, the calculation is 1 x 3, resulting in a final value of 3. This method is consistent with the definition of the diamond operation for positive integers as discussed in the Kaplan SAT Practice Test.

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y[tex]\diamond[/tex] is defined for all positive integer values of y as the product of all positive odd factors of 3y. For example, 6[tex]\diamond[/tex]= 1 x 3 x 9 = 27. What is the value of 4[tex]\diamond[/tex]?


Answer: 3


I tried this question and i got it wrong. This question is on the Kaplan SAT Practice Test.
I want to know how they got the solution to this problem. Can you provide an explanation for this question?

Thank You for your time...

Devansh.


BTW, I do not know where to post this question, so I decided this would be the best place...
 
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4[tex]\diamond[/tex] would be the product of all positive odd factors of 3(4) = 12...which would be 1 x 3 = 3.
 

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