How is the variation of the determinant of the metric computed?

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    Determinant Variation
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Discussion Overview

The discussion centers on the computation of the variation of the determinant of the metric in the context of varying Polyakov's action with respect to the metric on the world sheet. Participants explore mathematical expressions and seek clarification on the derivation process, particularly in relation to the square root of the determinant.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents an expression for the variation of the determinant, suggesting that δ(h)=2 h h_{αβ}δ(h^{αβ}) is a starting point.
  • Another participant challenges this expression, stating it is inaccurate and providing an alternative formulation: δ(h^2)=2h δh = 2 h^2 h^{αβ}δh_{αβ}, explaining the derivation involves considerations from general relativity and mathematics.
  • A third participant mentions deriving the result for the 2D case and requests a general proof or hint for broader applicability.
  • A fourth participant suggests starting from the relation det = exp Tr log as a potential approach to the problem.

Areas of Agreement / Disagreement

Participants express differing views on the initial expressions for the variation of the determinant, indicating a lack of consensus on the correct formulation. The discussion remains unresolved as participants continue to explore various approaches and seek clarification.

Contextual Notes

Some participants reference established methods from general relativity and mathematics, but the discussion does not resolve the assumptions or dependencies involved in the derivations presented.

christodouloum
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in varying an action like Polyakov's action with respect to the metric on the world sheet we have to consider the variation of the square root of the determinant. I have not found how to express the variation of the determinant of the metric. From reverse engineering I found that

\delta(h)=2 h h_{\alpha\beta}\delta(h^{\alpha\beta})

can someone give a hint on how this is computed?
 
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christodouloum said:
in varying an action like Polyakov's action with respect to the metric on the world sheet we have to consider the variation of the square root of the determinant. I have not found how to express the variation of the determinant of the metric. From reverse engineering I found that

\delta(h)=2 h h_{\alpha\beta}\delta(h^{\alpha\beta})

can someone give a hint on how this is computed?

That's inaccurate

\delta(h^2)=2h \delta h = 2 h^2 h^{\alpha\beta}\delta h_{\alpha\beta}

The indexed part in the last term of the muliple equality comes simply by considering the way one computes the inverse of a square matrix. The argument can be found in most GR books when discussing the HE action and, of course, in maths books when discussing integration on arbitrary manifolds.
 
Ok I derived it for the 2d case by writing out the components. Still can anyone provide a general proof or a hint for it?
 
Start from det = exp Tr log.
 

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