Image: http://imgur.com/pynKr8q(adsbygoogle = window.adsbygoogle || []).push({});

How is the boxed equation arrived at when looking at the step before?

I think I need clarification on a few key ideas:

in words, does < x | p | ψ > mean, "The momentum operator acting on the state vector, then projected onto the position basis"? If so, wouldn't that mean there would always be a factor of iћ since [x,p] = iћ?

Furthermore, is the reason the integral of |x'><x'| there just so you get <x'|ψ> and project ψ to the x' basis. I know it equals and identity matrix but can you do this?

Thank you

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# How is this equation for <x|P|x'> derived?

Loading...

Similar Threads - equation <x|P|x'> derived | Date |
---|---|

I Simplify the Dirac Energy Equation? | Monday at 11:18 AM |

I Use the Dirac Equation to calculate transition frequencies in Hydrogen | Mar 6, 2018 |

I Dirac's Equation vs. QFT | Feb 27, 2018 |

I Spin along x and y axes | Feb 25, 2018 |

I Can the Schrodinger equation satisfy Laplace's equation? | Feb 22, 2018 |

**Physics Forums - The Fusion of Science and Community**