How is τmax/rmax related to the second moment of area?

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SUMMARY

The relationship between τmax/rmax and the second moment of area (I) is established through the equation T = τmax/rmax ∫ r^2 dA. The integral of r^2 dA leads to the second moment of area, defined as I = ∫ r^2 dA. The confusion arises from the integration process, where the correct interpretation of the integral yields τ/rmax * I, clarifying the connection between shear stress and the second moment of area.

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Homework Statement



dT= τmax/rmax * r^2 dA

T = τmax/rmax ∫▒〖r^2 dA〗

as far as I am concerned integrating this will give us r^3/3 + c?
or am i thinking wrong, how did my teacher get the answer below in bold

Homework Equations


its not a great deal to do but I don't know how my professor got the following answer below


The Attempt at a Solution


the question is why the answer to this is

τ/rmax * Ip
 
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The second moment of area is defined as

I = \int_A r^2 dA


had you ∫r2 dr, then you'd get r3/3 + C
 

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