How many amino acid residues are there for the transmembrane domain?

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SUMMARY

The total number of amino acid residues in a transmembrane domain spanning a 4 nm bilayer, calculated using the rise per residue of an alpha helix at 1.5 Å, results in approximately 190 residues for seven transmembrane domains. The calculation is based on the formula: Total amino acids = (4 nm / 0.15 nm) + 1, yielding 27.66 amino acids per domain. Multiplying this by 7 gives a total of 193.62, which rounds to 190. The correct answer is option d.

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Homework Statement
The rise per residue of an alpaha helix is 1.5 Angstrom. A protein spans 4nm bilayer 7 times, through its transmenbrane alpha-helical domain.Aprroximately how many amino acid residues constitute the transmembrane domain of the protein
Relevant Equations
a) 105
b) 450
c) 30
d)190

Ans:d
Total no. of amino acid in each transmembrane domain = 4 nm/ 0.15 nm +1 =27.66
Total no. of amino acids in 7 transmembrane domains = 27.66 x 7 = 193.62 ≈ 190

Hence option d.

Is my approach correct?
 
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SanjuktaGhosh said:
Problem Statement: The rise per residue of an alpaha helix is 1.5 Angstrom. A protein spans 4nm bilayer 7 times, through its transmenbrane alpha-helical domain.Aprroximately how many amino acid residues constitute the transmembrane domain of the protein
Relevant Equations: a) 105
b) 450
c) 30
d)190

Ans:d

Total no. of amino acid in each transmembrane domain = 4 nm/ 0.15 nm +1 =27.66
Total no. of amino acids in 7 transmembrane domains = 27.66 x 7 = 193.62 ≈ 190

Hence option d.

Is my approach correct?

Yes, that looks correct to me.
 
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