MHB How Many Digits Are in $19^{9^9}$?

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    2017
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To determine the number of digits in the integer $19^{9^9}$, the formula for the number of digits in a number $n$ is given by $\lfloor \log_{10} n \rfloor + 1$. Applying this to $19^{9^9}$ involves calculating $\log_{10}(19^{9^9})$, which simplifies to $9^9 \cdot \log_{10}(19)$. The value of $9^9$ is a large number, and multiplying it by $\log_{10}(19)$ provides the total logarithmic value needed to find the digit count. The final result will yield the exact number of digits in $19^{9^9}$.
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Here is this week's POTW:

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How many digits are there in (decimal representation of) the integer $19^{9^9}$?

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No one answered last week's problem.(Sadface)

You can find the suggested solution below:
Note that $19^{9^9}=10^{9^9\log 19}=10^{9^9 \cdot 1.27875} \approx 10^{495,415,345.4}$, therefore the number $19^{9^9}$ requires $495,415,346$ digits.
 
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