How Many Grams of Sugar Can Be Assembled from 1 Mole of Each Atom?

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SUMMARY

The discussion centers on the assembly of sugar molecules (C6H12O6) from individual carbon (C), hydrogen (H), and oxygen (O) atoms, specifically when starting with 6.022x10^23 atoms of each type. Given that 1 mole of C6H12O6 weighs 180.15 grams, the scientist can produce one mole of sugar molecules from the available atoms. The limiting reactant in this scenario is determined to be the carbon atoms, as each molecule of sugar requires 6 carbon atoms, leading to the conclusion that the scientist will run out of carbon first.

PREREQUISITES
  • Understanding of mole concept and Avogadro's number (6.022x10^23)
  • Basic knowledge of molecular composition of glucose (C6H12O6)
  • Familiarity with stoichiometry and limiting reactants
  • Ability to perform mass calculations using molar mass (180.15g for C6H12O6)
NEXT STEPS
  • Study stoichiometry in chemical reactions
  • Learn about limiting reactants and how to identify them in chemical equations
  • Explore the concept of molar mass and its applications in chemistry
  • Investigate the molecular structure and properties of glucose (C6H12O6)
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding molecular assembly and stoichiometric calculations in organic chemistry.

Spartan Erik
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Homework Statement



A microscopic scientist is assembling sugar molecules (C6H12O6) from C, H, and O atoms. If he has 6.022x10^23 atoms of each type, how many grams of sugar molecules can he assemble? Which type of atom does he run out of first?

Homework Equations



1 mol = 6.02x10^23 atoms
1 mol C6H12O6 = 180.15g

The Attempt at a Solution



Well the problem states that he has 6.022x10^23 atoms of each type, meaning 1 mole of C, 1 mole of H, and 1 mole of O. I'm just not sure how to use this data to solve for this problem since it seems so strange

==================

NEVERMIND, Solved but thanks.
 
Last edited:
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If the person only has one mole of each atom, how many C6H12O6 can they make - what is the limiting component = which will they run out of first.
 

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