MHB How many integers in between \sqrt{19} and \sqrt{90}

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The integers between $\sqrt{19}$ and $\sqrt{90}$ are determined by identifying the smallest integer greater than $\sqrt{19}$ and the largest integer less than $\sqrt{90}$. Since $\sqrt{19}$ is approximately 4.36, the first integer greater than it is 5. Meanwhile, $\sqrt{90}$ is approximately 9.49, making the largest integer less than it equal to 9. Therefore, the integers between these two values are 5, 6, 7, 8, and 9. In total, there are five integers between $\sqrt{19}$ and $\sqrt{90}$.
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how many integers are between \sqrt{19} and \sqrt{90}
 
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prasadini said:
how many integers are between $\sqrt{19}$ and $\sqrt{90}$

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Do you understand what this question is asking? 19 lies between 16 and 25 so the first integer larger than [math]\sqrt{19}[/math] is what? 90 lies between 81 and 100 so the last integer less than [math]\sqrt{90}[/math] is what?

How many integers lie between [math]\sqrt{19}[/math] and [math]\sqrt{90}[/math]?
 
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