1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How many moles of MnO4- were added?

  1. Feb 12, 2013 #1
    Hello,

    I have no idea how to solve this...

    The initial mass of an unknown sample containing iron (II) is 0.512 g.
    12.6 mL of 0.01522 M KMnO4 is required to titrate the unknown to the endpoint.

    a) How many moles of MnO4- were added?
    b) How many moles of iron (II) must be present in the sample?
    c) How many grams of iron (II) must be present in the sample?
    d) What is the percent of iron present in the sample?


    I would know b, c, d, if I would know how to solve a. b, c, d, questions are simple, but I totally don't understand how to solve a. I wrote the rest so people who don't know similar exercise could get something more out of that topic.
    I know I shouldn't ask such a basics here, but I spent like an hour on YouTube and internet with no success. My professor is very unclear on every topic.

    Thank you so much for helping.
     
  2. jcsd
  3. Feb 13, 2013 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    Hi MrPoison, http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]


    Would it be any easier for you if the question was:

    a) How many moles of KMnO4 were added?


    because I think that's essentially what it's asking. :smile:
     
    Last edited by a moderator: May 6, 2017
  4. Feb 14, 2013 #3
    I have no idea, because that's what the question from the professor is. I literally rewrote it from the lab assignment.


    Is that right?

    a) How many moles of MnO4- were added?
    0.01522 moles/1 L x 0.0126L ≈ 0.0002 = 2x10-4 moles

    b) How many moles of iron (II) must be present in the sample?
    2x10-4 x 5 = 0.001

    c) How many grams of iron (II) must be present in the sample?
    0.001 moles of Fe2+ x 56g Fe/1 mole Fe = 0.056g Fe

    d) What is the percent of iron present in the sample?
    0.056g Fe/0.512 g unknown sample x 100 = 10.9%
     
    Last edited: Feb 14, 2013
  5. Feb 14, 2013 #4

    NascentOxygen

    User Avatar

    Staff: Mentor

    That's right. I wondered whether you were being tripped up by it asking for the Mn04- ions rather than KMnO4.
    That 5 seems to have sprung from nowhere, without explanation. You'd need to account for it if you want marks for this part.

    There are plenty of examples of oxidizing Fe(II) on the web for you to follow, e.g.,
    http://faculty.uml.edu/james_hall/84124/16.htm

    Good luck with your studies!
     
  6. Feb 15, 2013 #5

    Borek

    User Avatar

    Staff: Mentor

    It would be perfect, if not for the fact OP rounded it down, losing accuracy of the final result.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: How many moles of MnO4- were added?
  1. How many moles of XYZ (Replies: 1)

  2. How many moles. (Replies: 7)

Loading...