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How to calculate number of moles of H2O2 oxidized

  1. Sep 15, 2015 #1
    1. The problem statement, all variables and given/known data
    How many moles of hydrogen peroxide will be oxidized by 0.0045 moles of potassium permanganate in acidic solution?

    I am unable to think of how you get started?

    2. Relevant equations

    n - m/mm

    3. The attempt at a solution

    I've balanced the equation for an acidic solution: 2MnO4- + 6H+ + 5H2O2 -> 2Mn2+ + 5O2 + 8H2O

    I know, since it's balanced, the H202 has 5 moles per the 2 for MnO4-.

    I can't think of how to even get this started.
  2. jcsd
  3. Sep 15, 2015 #2


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    Education Advisor
    Gold Member

    How many moles of MnO4- do you have?

    If 5 moles of H2O2 are oxidized per 2 moles of MnO4- (I have NOT checked your arithmetic) then how many moles of H2O2 are oxidized by that many moles of MnO4-?
  4. Sep 15, 2015 #3
    So, I don't know if this is right, but .0045 is 9/4000th of 2, so then 9/4000*5 is the number of moles of H2O2 oxidized by .0045 moles of 2MnO4-.

    So, the answer should be .01125 moles?

    I don't know if that's right.
  5. Sep 15, 2015 #4


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    Staff: Mentor

    Looks OK.
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