How to calculate number of moles of H2O2 oxidized

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Discussion Overview

The discussion revolves around calculating the number of moles of hydrogen peroxide (H2O2) that will be oxidized by a given amount of potassium permanganate (MnO4-) in an acidic solution. The context is primarily homework-related, focusing on stoichiometry and chemical reactions.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents a balanced chemical equation for the reaction between MnO4- and H2O2, noting the stoichiometric ratio of 5 moles of H2O2 per 2 moles of MnO4-.
  • Another participant prompts for the number of moles of MnO4- available, suggesting that the stoichiometric relationship can be used to find the moles of H2O2 oxidized.
  • A third participant attempts to calculate the moles of H2O2 oxidized by using a fraction of the moles of MnO4- and arrives at a proposed answer of 0.01125 moles, expressing uncertainty about its correctness.
  • A later reply indicates that the previous calculation "looks OK," but does not confirm its accuracy.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the final answer, as uncertainty remains regarding the calculations presented.

Contextual Notes

The discussion includes assumptions about the balanced equation and the stoichiometric relationships, but does not resolve the correctness of the arithmetic or the final answer.

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Homework Statement


How many moles of hydrogen peroxide will be oxidized by 0.0045 moles of potassium permanganate in acidic solution?

I am unable to think of how you get started?

Homework Equations


[/B]
n - m/mm

The Attempt at a Solution



I've balanced the equation for an acidic solution: 2MnO4- + 6H+ + 5H2O2 -> 2Mn2+ + 5O2 + 8H2O

I know, since it's balanced, the H202 has 5 moles per the 2 for MnO4-.

I can't think of how to even get this started.
 
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How many moles of MnO4- do you have?

If 5 moles of H2O2 are oxidized per 2 moles of MnO4- (I have NOT checked your arithmetic) then how many moles of H2O2 are oxidized by that many moles of MnO4-?
 
So, I don't know if this is right, but .0045 is 9/4000th of 2, so then 9/4000*5 is the number of moles of H2O2 oxidized by .0045 moles of 2MnO4-.

So, the answer should be .01125 moles?

I don't know if that's right.
 
Looks OK.
 

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