How Many Non-Confusing Codes Can Be Formed from Distinct Digits?

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Robert Houdart
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Homework Statement



An intelligence agency forms a code of two distinct digits selected from 0, 1 , 2…, 9, such that the first digit of the code is nonzero. The code, handwritten on a slip, can, however, potentially create confusion when read upside down - for example; the code 91 may appear as 16. How many codes are there for which no such confusion can arise?
2. The attempt at a solution
This is the methodology I used:
Since the first digit cannot be zero, therefore it can be chosen in 9 ways while no restriction occurs on the second number, therefore it can be chosen in 10 ways.Thus, the total number of ways is 10*9=90...

Since 1,6,8,9 can create confusion, therefore there exist 12 such numbers which will create confusion. However the pair 69 and 96 do not come under this category.
 
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Since the first digit cannot be zero, therefore it can be chosen in 9 ways while no restriction occurs on the second number,...
... there are not nine possible choices for the 1st digit. Which other digits are excluded?
1,6,8,9 can create confusion,
... there you go ... so how many digits may be chosen from for the 1st number and how many for the second number?
the pair 69 and 96 do not come under this category.
... good thinking - these are numbers that are the same upside down ... are there others? i.e. what about 11?
 
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Mod note: This post was a response in a separate cross-posted thread.Ok, I think I got it. Since they are distinct numbers, the first digit can be chosen in 9 ways (except 0) while the second can also be chosen in 9 ways, making it 81 numbers instead of 90.. So am I right this time?
 
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well , considering 69 and 96 total number pertains to 10
 
(16,61) (18,81) (19,91) (68 ,86) (89, 98) i think these are all (actually total number of numbers were 81 instead of 90 (digits must be distinct)