How much energy does the kettle transfer?

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SUMMARY

The discussion centers on calculating the energy transferred by an electric kettle labeled "230V, 2.3kW" over a duration of 2.5 minutes. The key formula used is the relationship between power and energy transfer, expressed as E = Pt, where E is energy in joules, P is power in watts, and t is time in seconds. The calculation reveals that the kettle transfers energy without needing the electron charge or voltage for this specific problem. Understanding this relationship clarifies the concept of energy transfer in physics.

PREREQUISITES
  • Understanding of basic physics concepts, particularly energy and power.
  • Familiarity with the formula E = Pt for energy calculations.
  • Knowledge of units of measurement: watts, joules, and seconds.
  • Basic comprehension of electric kettles and their specifications.
NEXT STEPS
  • Research the calculation of energy transfer in different electrical appliances.
  • Learn about the relationship between voltage, current, and power in electrical circuits.
  • Explore the principles of thermodynamics related to energy conversion.
  • Study the efficiency of electric kettles and how it affects energy consumption.
USEFUL FOR

This discussion is beneficial for students studying physics, electrical engineering students, and anyone interested in understanding energy transfer in electrical devices.

Christopher
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I know that Tom wants us to at least have one go at answering the question ourselves but Ihave been haunted by this question for almost a week now and I don't feel ay closer to answering it.

I have been given the electron charge which is 1.6*10-19 C and I have been given the question "An electric kettle is labelled "230V, 2.3kW". It takes 2.5 minutes to boil some water.
How much energy does the kettle transfer?

How am I meant to answer this questin if I am not given some sort of other energy to compare the electric energy to?
Please help

Chris
 
Last edited:
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ps: the italic -19 is meant to be a small -19 above to the right of the 10.
 
You have been given voltage and power. Power is the rate of energy transfer(P = E/t) . So "watts" = "joules"/"seconds" therefore, E = Pt "joules" = "watts" x "seconds" . You don't need the charge of the electron nor the voltage for this problem.
 
Thankyou :biggrin:
It never seemd to occur to me that power is the energy transfer but now it makes so much sense I feel quite stupid...lol! :smile:
 
Last edited:
Christopher said:
... but now it makes so much sense I feel quite stupid...lol! :smile:

That's what Physics is all about!
 

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