Glycine which has a pKa of 9.6 can exist in protonated form (-NH3+) or as the free base (-NH2) because of the reversible equalibrium R-NH3+ <------> R-NH2 + H+.
How much 5 M KOH must be added to 1.0 L of 0.1 M glycine at pH 9 to bring the pH to exactly 10?
The Attempt at a Solution
I have spent a couple hours trying to figure this out but don't really know where to start. A couple hints might point me in the right direction