How much heat in joules must be added to 0.841 kg of aluminu

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Homework Statement


How much heat in joules must be added to 0.841 kg of aluminum to change it from a solid at 130 °C to a liquid at 660 °C (its melting point)? The latent heat of fusion for aluminum is 4.0 x 105 J/kg.

Homework Equations


Q = mL
Total = mc∆t + mL = m(c∆t +l)

The Attempt at a Solution


i think it is it .841(.9(660-130) + 4*105) but the answer i get isn't right
 

Answers and Replies

  • #2
Nathanael
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The Attempt at a Solution


i think it is it .841(.9(660-130) + 4*105) but the answer i get isn't right
That 0.9, the specific heat of aluminum, is not in standard units. It’s 0.9 kilojoules / kg (or equivalently, 0.9 J / g) and not 0.9 J / kg
 
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Also, that heat of fusion should be 400000 J/kg (actually 321000 J/kg according to an internet source).
 
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Nathanael
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Also, that heat of fusion should be 400000 J/kg (actually 321000 J/kg according to an internet source).
I thought it was weird to say 4*105 hahaha 10^5 makes a lot more sense o:)
 
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That 0.9, the specific heat of aluminum, is not in standard units. It’s 0.9 kilojoules / kg (or equivalently, 0.9 J / g) and not 0.9 J / kg
I thought it was weird to say 4*105 hahaha 10^5 makes a lot more sense o:)
Yea I didn't realize it changed it to that.
 

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