How much heat in joules must be added to 0.841 kg of aluminum to change it from a solid at 130 °C to a liquid at 660 °C (its melting point)? The latent heat of fusion for aluminum is 4.0 x 105 J/kg.
Q = mL
Total = mc∆t + mL = m(c∆t +l)
The Attempt at a Solution
i think it is it .841(.9(660-130) + 4*105) but the answer i get isn't right