How negative sign appeared out of nowhere?

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SUMMARY

The discussion centers on the resolution of forces into components for a triangle with sides 3, 4, and 5. The resultant force was calculated as ##\Sigma F_x = \textbf{-}2*\frac{4F}{5}##, highlighting a discrepancy in the vertical component, which was incorrectly noted as 4/3 F instead of the correct 4/5 F. The conversation emphasizes the importance of accurately identifying the moments about a specific point when analyzing forces.

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  • Understanding of vector resolution in physics
  • Knowledge of triangle properties, specifically the 3-4-5 triangle
  • Familiarity with force components and resultant forces
  • Basic principles of static equilibrium and moments
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  • Study vector resolution techniques in physics
  • Learn about static equilibrium and how to calculate moments
  • Explore the properties of right triangles, particularly the Pythagorean theorem
  • Investigate common mistakes in force component calculations
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Students in physics, engineers working with static systems, and anyone involved in mechanics or force analysis will benefit from this discussion.

Benjamin_harsh
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Homework Statement
Determine the required magnitude of force F in the resultant couple
moment on the frame is 200 lb.ft clockwise.
Relevant Equations
##\Sigma F_x = \textbf{-}2*\frac{4F}{5}##
I have to find resultant for this couples:

243987


My sir resolved given forces into components like this:

243988


He considered Fx couples for sides 3,4,5 triangles:

243989


He wrote resultant force for this above diagram: ##\Sigma F_x = \textbf{-}2*\frac{4F}{5}##
 
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You appear to have written the vertical component as 4/3 F, twice, instead of 4/5, and the horizontal once as 4/3 instead of 3/5.

Which point are you taking moments about?
 

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