The discussion centers on the comparison of the value of (4/3)^4 and the irrational number π, which is approximately 3.1415926535. The calculated value of (4/3)^4 is approximately 3.1605, which agrees with π to one decimal place, specifically "3.1". The discrepancy arises in the second decimal place, where (4/3)^4 yields "6" instead of "4". Participants confirm that there is no typo in the calculation, and the values are accurately represented.
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Is there a typo in this? The calculation seems to give a result that is not accurate at all.RTCNTC said:The value of the irrational number π, correct to ten decimal places (without rounding) is 3.1415926535. By using your calculator, determine to how many decimal places does the quantity (4/3)^4 agree with π.
topsquark said:Is there a typo in this? The calculation seems to give a result that is not accurate at all.
[math]\left ( \frac{4}{3} \right ) ^4 \approx 3.1605[/math]
You can take it from there.
-Dan
Couldn't you have just done this? Using a calculator, as the problem says, (4/3)^4= 3.1604938271604938271604938271605. That "agrees with π" to one decimal place ("3.1") since it differs in the second decimal place ("6" instead of "4").RTCNTC said:The value of the irrational number π, correct to ten decimal places (without rounding) is 3.1415926535. By using your calculator, determine to how many decimal places does the quantity (4/3)^4 agree with π.