How to answer a Combinations question

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    Combinations
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Discussion Overview

The discussion revolves around solving a combinations problem related to selecting numbers in a lottery context, specifically Lotto 649, where participants explore the correct application of the combinations formula and the order of operations in mathematical expressions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant initially attempts to use the combinations formula but expresses uncertainty about the legality of simplifying the factorial expression.
  • Another participant suggests that the formula is missing parentheses, clarifying the correct interpretation of the combinations formula.
  • A subsequent reply confirms that using the corrected formula leads to the answer of 13,983,816, but does not assert it as definitive.
  • Another participant emphasizes the importance of understanding the derivation and limitations of the formula, referencing common misunderstandings related to order of operations.
  • A later post provides links to external resources on order of operations and combinations, indicating a broader context for the discussion.

Areas of Agreement / Disagreement

Participants generally agree on the correct application of the combinations formula, but there is no consensus on the initial approach taken by the first participant. The discussion includes varying levels of understanding regarding mathematical expressions and their interpretations.

Contextual Notes

There are unresolved aspects regarding the initial confusion over the factorial simplification and the implications of order of operations in mathematical expressions.

Biochemgirl2002
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Question: When playing Lotto 649, you must pick six numbers from the numbers 1, 2, …, 49. In how many ways can you do this?

My attempt

n!/r!(n-r)! = 49!/6!(49-6)!
(49x48x47x46x...x1)/(6x5x4x3x2x1)(43x42x41x40x...x1)

=0.06 .
(edit: i redid the question and just made it (49x48x47x46x45x44)/(6!) and i got 13,983,816. this seems like it could be the right answer but i am still hesitant because I am not sure that is legal to just remove the 43! from the denominator)

this is definitely wrong, since the number should be huge, but I am not sure how to approach the correct answer
 
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I think your formula is missing some parens:

## n! / r! (n-r)! ## which is in fact ##\frac {n!} {r!} (n-r)! ## should be ##\frac {n! } {(r! (n-r)!)} ##

by way of explanation, you choose 6 numbers out of 49 which is 49*48*47*46*45*44 or
49! / (49-6)! and now since the order doesn't matter you divide by 6!
 
Alright, so if i did the equation

(49*48*47*46*45*44)/(6*5*4*3*2*1) ,
so therefore the answer would be 13,983,816 ?
 
Just understand the meaning of your formula ie basically learn how to derive it and understand how it works and what its limitations are...

Walk around and amaze your friends by computing probabilities of related events.

The mistake you made here is a common meme among folks studying the order of math operations in fuzzy expressions that's why I added the parens to make it clear.

https://www.insider.com/hard-viral-...#this-viral-math-question-has-two-solutions-1
In particular, look at the 6/2(1+2) example. People really get confused by it with some thinking its
##\frac {6} {2} (1+2) = 9## versus some thinking its ## \frac {6} { 2 * (1+2)} = 1##

Do you see the confusion and why the first one is how we interpret the expression with modern PEMDAS conventions?
 

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