How to Calculate Poisson Distribution Probabilities?

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SUMMARY

The discussion focuses on calculating probabilities using the Poisson distribution, specifically for a radioactive substance with a mean count of 25 disintegrations per minute. The probability mass function for the Poisson distribution is defined as P[X=k]=λ^k e^(-λ)/k!. In this context, λ represents the average rate of occurrence, while k denotes the number of occurrences. The participants aim to find the probabilities of observing no disintegrations and more than two disintegrations within a 12-second interval.

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mathsforumuser
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Hi guys I got a question on the poisson distribution and never previously done stats at all.

It follows:

The mean count of a radioactive substance is 25 disintegrations per minute. Using the Poisson distribution, find the probability that, in a time of 12 seconds, there are-

i) No disintegrations

ii) More than 2 disintegrations
 
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Hi mathsforumuser,

Welcome to MHB! :)

When working with any discrete probability distribution, we often need to use the probability mass function. For a Poisson distribution this is:

$$P[X=k]=\frac{\lambda^k e^{-\lambda}}{k!}$$

For this problem, what is $\lambda$? What is $k$?
 

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