How to Calculate the Velocity and Impact Speed of a Ball Launched by a Spring?

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SUMMARY

The discussion focuses on calculating the velocity and impact speed of a ball launched by a spring in a physics problem involving conservation of energy. The spring constant is specified as 1000.0 N/m, with a spring compression of 4 cm and a ball mass of 55 g. The ramp height is 15 cm, and the table height is 1.2 m. Key equations include the conservation of energy formula, which simplifies to vf = √(2gh) for determining the final velocity of the ball just before it hits the floor.

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Homework Statement



A child's game consists of a block that attaches to a table with a suction cup, a spring connected to that block, a ball, and a launching ramp. The spring has a constant k. the ball has a mass m, and the ramp raises a height h. The spring is compressed a distance S in order to launch the ball. when the ball leaves the launching ramp its velocity makes and angle with respect to the horizontal.

1 Calculate the velocity of the ball when its leaves the launching ramp (both the magnitude and the direction. Be sure to specify your coordinate system)

2. The spring constant = 1000.0 N/m the spring compression is 4. cm the ball's mass is 55 g, the height of the ramp is 15 cm and the top of the table is 1.2 m above the floor. With what speed will the ball hit the floor?



Homework Equations


Delta y = Vft+1/2gt2
speed=distance/time

The Attempt at a Solution



I really do not have a clue where to start I have been thinking on how to solve it but all i have done is write down some equations that may be helpful but i really don't know if they are helpful in this problem. Can someone please help me? thanks
 
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bmandrade said:

Homework Statement



1 Calculate the velocity of the ball when its leaves the launching ramp (both the magnitude and the direction. Be sure to specify your coordinate system)

2. The spring constant = 1000.0 N/m the spring compression is 4. cm the ball's mass is 55 g, the height of the ramp is 15 cm and the top of the table is 1.2 m above the floor. With what speed will the ball hit the floor?

Have you considered conservation of energy?
 
yes i had that equation KEf+PEf=KEi+PEi

so 1/2 mvf2 + mgh = 1/2 mvi2 + mgh

so in this case masses cancel and i would have to solve for vf
 
bmandrade said:
yes i had that equation KEf+PEf=KEi+PEi

so 1/2 mvf2 + mgh = 1/2 mvi2 + mgh

so in this case masses cancel and i would have to solve for vf

Sounds fine by me.
 
ok well i know that 1/2mvi^2 = 0 and the mgh final should be 0 too

in that case vf= square root of 2gh

however i got stuck because i there is no value given for h is there a way i can find h or am i suppose to have another equation
 

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