How to Correctly Integrate S(x(x+1)^(1/2)) dx?

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The discussion focuses on the integration of the function S(x(x+1)^(1/2)) dx, where participants analyze the steps taken to solve the integral. The correct substitution involves using u = x + 1, leading to the integral S((u-1)√u) du. The final correct expression for the integral is (2/5)(x+1)^(5/2) - (2/3)(x+1)^(3/2) + C. Participants emphasize the importance of expressing the result in a simplified form, specifically as √(x+1) multiplied by a polynomial in x.

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Homework Statement


S(x(x+1)1/2) dx

Homework Equations


The Attempt at a Solution


u=x+1
du=1
x=u-1

S(x(u)1/2) du

S(((u-1)(u)1/2) du

S((u2-u)1/2) du

S(u-u1/2) du

S((1/2)u2-(2/3)u3/2)

=(1/2)(x+1)2-(2/3)(x+1)3/2) + COnline homework says it's wrong... Where did I mess up?
 
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Hi tjohn101! :smile:

(have an integral: ∫ :wink:)
tjohn101 said:
S(((u-1)(u)1/2) du

S((u2-u)1/2) du

S(u-u1/2) du

Neither of these lines is correct. :redface:

(u-1)√u = u√u - √u :wink:
 
Ahhhh thank you. I didn't notice I had done that :/
 
Hmmm I ended up getting

(2/5)(x+1)5/2-(2/3)(x+1)3/2 + C

Sound right?
 
Hi tjohn101! :smile:

(just got up :zzz: …)

Yes :smile:but perhaps you should put it in the same form as the question, ie √(x+1) times an ordinary polynomial in x ? :wink:
 
Thank you for your help!
 

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