How to Derive Potential Energy for SHM in Terms of Frequency?

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SUMMARY

A particle of mass m executing simple harmonic motion (SHM) with frequency f has a potential energy described by the equation V(x) = 2π²f²mx². This relationship is derived from the known equation for potential energy in SHM, V(x) = 1/2mω²x², where ω is the angular frequency defined as ω = 2πf. The conversion from the force exerted by a spring, as described by Hooke's Law, to potential energy is a fundamental concept in classical mechanics.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with Hooke's Law
  • Knowledge of angular frequency (ω) and its relationship to frequency (f)
  • Basic principles of potential energy in conservative forces
NEXT STEPS
  • Study the derivation of potential energy in simple harmonic motion
  • Explore the relationship between force and potential energy in conservative systems
  • Learn about the applications of Hooke's Law in various physical systems
  • Investigate the implications of frequency in oscillatory motion
USEFUL FOR

Students of physics, particularly those studying classical mechanics and simple harmonic motion, as well as educators seeking to clarify the relationship between force and potential energy.

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Homework Statement



I have been asked to show that a particle of mass m executing simple harmonic motion with frequency f, has a potential energy

V(x) = 2\pi^{2}f^{2}mx^{2}

Homework Equations





The Attempt at a Solution



I know that V(x) = 1/2m\omega^{2}x^{2} and that \omega=2\pif

but i can't find how to show this anywhere - not in the lecture notes, my books or the internet - I am finding this quantum mechanics course a massive step up from all the other areas of physics!
 
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This is a problem that could be given to you in a classical mechanics course aswell.

What is the Spring-force (Hooks law), and how do you go from a (conservative)-Force to the potential?
 

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