How to determine appropriate wter pump

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Discussion Overview

The discussion revolves around determining the appropriate horsepower (hp) or kilowatt (kw) needed for a water pump to introduce a constant volume of water into a 60 ft tall water tank. Participants explore the calculations and considerations involved in selecting a pump for this application.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks for clarification on the math required to determine the hp/kw needed for the pump.
  • Another participant questions the necessity of a pump if the volume of water is constant.
  • Some participants suggest that the flow rate needs to be defined in specific units, such as gallons per minute or cubic feet per hour.
  • There are mentions of using static pressure and flow rate to calculate power, with a formula provided for hydraulic horsepower and pump horsepower.
  • One participant expresses uncertainty about how to perform the calculations, specifically regarding water pressure and flow rate.
  • A suggestion is made to consult with a pump vendor to determine the best pump based on specific needs and conditions.

Areas of Agreement / Disagreement

Participants present various viewpoints on the calculations and requirements for selecting a pump, with no consensus reached on the necessity of the pump or the specifics of the calculations.

Contextual Notes

Some assumptions about flow rates and pump efficiency are not fully detailed, and the discussion includes unresolved questions about specific calculations and definitions.

jmikl
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A constant volume of 1800 cf of water needs to be introduced into the base of a 60 ft tall (15x15) water tank. I need to determine the hp/kw needed in order to do this. Can anyone explain the math on determining this?

Thx

Jeff
 
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If the volume of water is constant, what's the pump for?
 
continuous flow, costant flow.
 
You need the flow in, say, gallons per minute, cf per hour, or lbs per hour,,,,,,,,

amount of water / amount of time

after that it's straightforward.

Good Luck
 
cubic feet per minute flow

Thx
 
Static pressure times flow rate = power. Divide by pump efficiency to get motor power.
 
Static pressure times flow rate = power. Divide by pump efficiency to get motor power.

Thx Russ. I am still not sure how to calculate it.

25.92 (water pressure at 80 ft) xxxx gpm ?

jeff
 
jm,

Hydrualic HP = lbs of liquid per minute x head (in feet) / 33,000

Pump HP = Hyd HP/Pump Efficiency

After you work this out, call your trusted pump vendor/mnfr, and work out w them the most logical pump to purchase based on your specific needs/ conditions.
 

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