- #1

Arooj

- 40

- 0

## Homework Statement

I had to a lab on the Newton's second law of motion, and one of the direction was to "determine the force of friction" from a graph I constructed. The experiment is similar to this: http://people.sc.fsu.edu/~dduke/manual/gp1.htm [Broken]

This image of the data is a lot cleaner than my representation of it.

Data:

Trial Mass Weight Hanger (g) Time Average (sec) Acceleration (m/s^2) Force(N) Theoretical Acceleration (m/s^2)

1 15 3.320 0.0998 0.1472 0.0934

2 25 2.519 0.1734 0.2453 0.1556

3 35 2.261 0.2152 0.3434 0.2179

4 45 1.904 0.3034 0.4415 0.2801

5 55 1.761 0.3547 0.5396 0.3424

6 65 1.602 0.4286 0.6377 0.4047

7 75 1.496 0.4915 0.7358 0.4669

8 85 1.283 0.6683 0.8339 0.5292

Experimental Slope 1.4018

Theoretical Slope 1.5758

Total mass of system 1.5758 kg

## Homework Equations

F = uN = umg ( But we weren't given a coefficient of friction, so I wonder if calculating frictional force is even possible)

Fk = -F (Fk = kinetic force of friction)

## The Attempt at a Solution

I think you would subtract 1.5758 - 1.4018 to get the difference in kg, and then multiply that by an acceleration of 1 to get the coefficient of friction 0.174. Then I guess you multiply that by the 1.5758 to get the force of friction 0.2742 N.

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