How to find the aceleración and the rope forcé Fs?

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SUMMARY

The discussion focuses on solving a physics problem involving the calculation of acceleration and the rope force (Fs) in a system with two blocks. The initial attempt used the formula Fs = Fg1 + Fg2 + Ft1 + Ft2, leading to an incorrect acceleration calculation of 4.9 m/s². Participants emphasized the importance of defining variables clearly and recommended using Free Body Diagrams (FBD) to analyze the forces acting on each block separately. A more effective approach involves introducing a variable for tension (T) to simplify the equations.

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neon495
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<< Note -- formatting fixed up by a Mentor >>

1. Homework Statement


Please see the attached image for the problem statement.

Homework Equations

The Attempt at a Solution


[/B]
I uses the formula
Fs = Fg1 +Fg2 + Ft1 + Ft2
I asumed the acceleration is equal to (F1+F2)/ m
(4,9+19,6)/3 = 4,9ms^-2

but I am not Sure if this is correct
 

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neon495 said:
I uses the formula
Fs = Fg1 +Fg2 + Ft1 + Ft2
I asumed the acceleration is equal to (F1+F2)/ m
(4,9+19,6)/3 = 4,9ms^-2

but I am not Sure if this is correct
No, it's not correct.

I don't see where you've defined any of the forces that you are summing. What are F1 and F2 in your acceleration expression (which does not look correct to me)? You should always define your variables clearly to avoid confusion of others trying to interpret your work.

Did you start by drawing Free Body Diagrams for both blocks? This is a must for these kinds of problems.
 
neon495 said:
not Sure if this is correct
As gneill posted, it is wrong.
To avoid confusing yourself, it is safer to create an unknown T for the tension then consider the forces and acceleration of each mass separately. When you have those equations you can combine them to eliminate T.
 

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