MHB How to Find the Longest Side of Triangle ABC with Given Medians?

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In triangle ABC, where ∠ABC is a right angle, two medians are given: AM = 5 and CN = 2√10. The lengths of sides BC and AB can be expressed as BC = 2BM and AB = 2NB, with BM and NB represented as x and y, respectively. By applying the Pythagorean theorem to triangles ABM and NBC, a system of equations can be established to solve for x and y. Substituting these values into the expression for AC will yield the length of the longest side of triangle ABC.
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In triangle ABC, ∠ABC = 90◦
. A median is drawn from A meeting BC at M such
that AM = 5. A second median is drawn from C meeting AB at N such that
CN = 2√10.
Determine the length of the longest side of triangle ABC

I have no idea where to even start on this one
 
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Welcome, Ilikebugs! (Wave)

Let $BM = x$ and $NB = y$. Since $M$ is the median of $BC$, $BC = 2 BM = 2x$; since $N$ is the median of $AB$, $AB = 2NB = 2y$. Now try to do the following:

  1. Find an expression for $AC$ in terms of $x$ and $y$ (Hint: Use the Pythagorean Theorem).
  2. Consider triangle ABM, and write an equation involving $x$ and $y$ using the Pythagorean theorem. Do the same for triangle $NBC$.
  3. Solve the resulting system of equations. Take your $x$-solution and $y$-solution, and plug it into the expression for $AC$ to obtain the answer.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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