MHB How to Find the Ordinate of P for Minimum AB in a Quadrant Curve?

[leprofece]

P is a point in the first quadrant on the curve: y = 7 - x² . By P is drawn tangent to the curve, and A and B are points at which cut to the coordinate axes. Find the ordinate of P so that AB is minimum

Answer = 49/8

 

[MarkFL]

What have you tried and where are you stuck? We do expect for people to show what they've tried so we have at least some idea where they are in the problem and how we can assist them to proceed...when you just post the problem, we have no idea how to best help you. :D

 

[leprofece]

What have you tried and where are you stuck? We do expect for people to show what they've tried so we have at least some idea where they are in the problem and how we can assist them to proceed...when you just post the problem, we have no idea how to best help you. :D

ok If P (x₀,y₀)
the tangent must be yy₀+xx₀
the interception of the curve xith x axe is +/-sqrt7 and y = 7
I don't know how to assemble the equations
How can I proceed?