Benzoic acid/biphenyl mixture is mixed with diethyl ethe(CH3CH2-O-CH2CH3). The solution is placed in a separatory funnel and sodium hydroxide is mixed in.
The bottom layer, H2O, NaOH and benzoic acid is then placed in a flask where it is mixed with HCl, chilled and then suction filtrated. Solid sample left over.
The top layer which consists of biphenyl, H2O trace and ether is poured into a flask. Anhydrous potassium carbonate (K2CO3) is mixed into the solution. It is then distilled. Solid sample left over.
For percent recovery, the initial mass weighed was the combination of benzoic acid and biphenyl mixture. Do I use the combined weight and divide that into the weight of the pure compound each? Or do I combine it?
I started the relevant equations and wanted to double check to see if I was on the right track and am not missing a relevant equation.
Percent recovery = (mass of pure product recovered/ mass of crude product used) x 100
Benzoic acid - C6H5COOH
Biphenyl - C12H10
The Attempt at a Solution
Percent recovery of benzoic acid - (0.9g/2.08g) x 100 = 43%
Percent recovery of biphenyl - (27.11g/2.08g) x 100 = 1303..... this is where I run into a problem. 27.11g seems extremely high.
Bottom layer :
C6H5COOH + NaOH -> H2O + NaC7H5O2
NaC7H5O2 + H2O + HCl -> C6H5COOH (solid product) + H20 + NaCl
C12H10 + C4H10O ->
A little stuck here