How to Solve an Equation with Natural Logarithms?

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SUMMARY

The discussion focuses on solving the equation x + ln(6 - 2e^x) = ln(4). The key solution involves taking the exponential of both sides to eliminate the natural logarithm. Participants emphasized the importance of understanding the properties of logarithms and exponentials, particularly the relationship e^(a+b) for simplifying expressions. The final solution was confirmed by the original poster after applying these concepts.

PREREQUISITES
  • Understanding of natural logarithms and their properties
  • Familiarity with exponential functions
  • Basic algebraic manipulation skills
  • Knowledge of solving equations involving logarithmic expressions
NEXT STEPS
  • Study the properties of natural logarithms, specifically ln(a - b)
  • Learn how to apply the exponential function to solve logarithmic equations
  • Explore the concept of logarithmic identities and their applications
  • Practice solving various equations involving natural logarithms and exponentials
USEFUL FOR

Students studying algebra, particularly those tackling logarithmic equations, as well as educators looking for examples of solving equations with natural logarithms.

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[SOLVED] Simple algebraic equation

Homework Statement


I got stuck on solving an equation on this step...
x+ln(6-2e^x)=ln4


Homework Equations





The Attempt at a Solution



I just don't know how to do ln(6-2e^x)... in general, what's ln(a-b)?

Thanx in advance.
 
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There is no form for ln(a-b). Take e to the power of both sides of your equation. You do know a form for e^(a+b), right?
 
i got it thanks a lot
 

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