How to Solve Tricky Integrals Involving x^3*sin(x^2) and Rational Functions?

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Lodve
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Hi I'm struggling solving this integration:
[tex]x^3 * sin x^2[/tex]
My idea to solve this one is to apply integration by parts, but I can't get through using it.

[tex]\frac{4x+2}{x^2(x^2+2)}[/tex] this seems a hard nut to crack.
 
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If you want to use integration by parts for the first one, there is a certain substitution that would make it quite simple. Can you see it?
 


Hmmm not sure, what if a let the u equal to x^2 and derive it so that I get 2x?
 


u=x^2
du=dx*2x

so your argument would be:

1/2u*sin(u)du

which is easier to do parts on.
 


For the second integral, use Partial Fraction Decomposition:

[tex] \frac{4x+2}{x^2(x^2+2)} = \frac{Ax+B}{x^2}+\frac{Cx+D}{(x^2+2)}[/tex]

Each of the resulting fraction could be integrated by u, du substitution.

http://en.wikipedia.org/wiki/Partial_fraction