How would you solve the following physics acceleration and free fall problem?

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SUMMARY

The physics problem involves a package dropped from a helicopter traveling upward at 10.0 m/s. The calculations reveal that the helicopter was 25.025 meters high when the package was released and 60.025 meters above the ground when the package impacted. To determine the maximum height the package reaches after release, the equation v = v_0 + at is utilized, leading to a maximum height of 30.227 meters. These calculations are confirmed through graphical analysis of position, velocity, and acceleration over time.

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Homework Statement


A package is dropped from a helicopter. Note that both the helicopter and package are traveling upward at 10.0m/s when the package is released. If the package takes 3.5 seconds to hit the ground, how high was the helicopter when the package was released?
If the helicopter's velocity does no change, how far above the ground will the helicopter be located when the package hits the ground?
What is the maximum height above the ground that this package reaches after it was released by the helicopter?

Homework Equations



The Attempt at a Solution


So far I've tried to answer the first two questions question and got that the helicopter was 25.025m high when the package was released and was 60.025m above the ground when the package hit the ground. Of course I'm not sure if this is correct and I'm totally unsure about how to solve the last question about what the maximum height above the ground that the package reached.

I made an x vs. t graph, a v vs. t graph, and an a vs. t graph to help with solving these as well.
 
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your first answers are correct.

use v = v_0 + at to find the time of maximum altitude where v = 0
 
So for the last question:
"What is the maximum height above the ground that this package reaches after it was released by the helicopter?"

Would the answer be 30.227m?

Thanks for your help!
 

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