I feel like a dunce. I can't find the error

1,005
64
In line 7, B - C - A = 0. The equation A*0 = B*0 does not imply that A = B.
 

pwsnafu

Science Advisor
1,080
85
The use of A, B and C is to obfuscate what is going on. If you substitute in the values, it is obvious.

Line 7:
[tex]A(B-C-A) = B (B-C-A)[/tex]
He then divided by B-C-A.

But B-C-A = 0, and so Line 7 is nothing more than
[tex]4 \times 0 = 5 \times 0[/tex]
 
867
60
I see.
So the lesson learned here is that when deviding both sides of an equation by anything the resulting equation is only valid where that thing ≠0
Thanks.
 
32,837
4,556
I see.
So the lesson learned here is that when deviding both sides of an equation by anything the resulting equation is only valid where that thing ≠0
Thanks.
A shorter way of saying that is that you can't divide both sides of an equation by zero.
 

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