# I have some problems with units, can someone help me?

• A  Can someone help me to calculate the unit of gamma from the eq. (2.3). From Eq. (2.2) I assume, it must be [s^-1], but I can not produce it.

Thanks
Amelos Related Quantum Physics News on Phys.org
Homework Helper
Gold Member
A couple of questions and comments is what is "C"? and it is kind of surprising to see an ## \epsilon_o ## to the 3rd power in the denominator without an ## e^6 ## where ## e ## is the elementary charge in the numerator. Otherwise a ## \mu_o ## to the 3rd power should be present since speed of light ## c=1/\sqrt{\mu_o \epsilon_o} ##. And I assume ## n_1 ##, ## n_2 ##, and ## n_3 ## are dimensionless=either indices of refraction or photon numbers...editing... additional comment is it resembles something found in the early chapters of Boyd's Non-Linear Optics book, but the exponents on the terms including the sinc function are different.(Boyd's book has ## sinc^2 (\Delta k l/2) ##). editing... Additional item=when comparing to Boyd's result, I think perhaps this even needs a ## \Gamma^2 ## and the operator terms may need to be ## (a_1^{+}a_1^{-})( a_2^{+}a_2^{-}) ## (number operators), but perhaps somehow a second order term arises out of this Hamiltonian,(from perturbation theory, etc.), that makes the results agree. ... additional edit: It appears the author is doing sum-frequency generation which is covered in pages 62-66 of Boyd's book using coupled-wave equations. The question is, does the author get the Hamiltonian correct and get one that is consistent with Boyd's book? I am on a learning curve as well with this material, but at least this might help you to figure out what the author of your textbook is doing.

Last edited:
Homework Helper
Gold Member
And a follow-on to post #2: I think Fermi's Golden Rule or a similar relation may be used to get from the Hamiltonian given by your textbook to the form of the intensity or power equation result that is given in Boyd's book. Just maybe the two are completely consistent, but it would be neat to be able to show that if that is the case.

Hey Charles,

C: light of speed
n1,n2,n3 are unitless refractive indices
deff : V/m
I3: intensity of pump (assume W/m^2)
I am not that familiar with quantum mechanics. I thought maybe he is not doing the calculation in SI units.

Thanks
Halil

Homework Helper
Gold Member
The subject is difficult enough (a detailed quantum mechanical calculation in non-linear optics) that if you are really interested in it, I would recommend trying to find the same calculation in another textbook to compare the results. I am thinking there should perhaps also be an ## a_3^{+} ## creation operator in the Hamiltonian. In any case I got a number of the terms in his ## \Gamma ## to agree with Boyd's result by using Fermi's golden rule, but so far I don't have complete agreement.

I have been looking at this. I just can't get the amps ( or coulombs) to cancel.