Ideal/Submodule Query - Proving R is Principal Ideal Domain

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SUMMARY

The discussion centers on proving that if R is a principal ideal domain (PID), then every submodule of a free module is finitely generated. The proof begins with a free module F isomorphic to R^n, utilizing induction on n. In the base case where n=1, it is established that a submodule P of F, which is isomorphic to R, must also be an ideal in R. The confusion arises in connecting the properties of P as a submodule to its status as an ideal in R.

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  • Understanding of principal ideal domains (PIDs)
  • Familiarity with free modules and their properties
  • Knowledge of module theory and submodules
  • Induction techniques in mathematical proofs
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  • Study the properties of principal ideal domains (PIDs)
  • Learn about free modules and their structure in module theory
  • Explore induction proofs in abstract algebra
  • Investigate the relationship between submodules and ideals in ring theory
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Mathematicians, particularly those specializing in abstract algebra, module theory, and anyone interested in the properties of principal ideal domains and their implications for submodules.

Ad123q
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Hi,

This has came up in a proof I'm going through, and need some guidance.

The proposition is that if R is a principal ideal domain, then every submodule of a free module is finitely generated.

The proof starts let F isomorphic to R^n be free, with basis {e1, ... , en}.
Let P be a submodule of F.
Use induction on n.
Case n=1: F isomorphic to R (R is a module over R). Then P is a submodule of F which is isomorphic to R. This then implies that P is an ideal in R.

This is where I'm stuck, I'm not sure how P a submodule of F which is isomorphic to R implies that P is an ideal in R.

Any help appreciated - just ask if you need more background on the proposition.

Thanks!
 
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the statement is that every submodule of a finitely generated free module is finitely generated and free of same or smaller rank. the proof is by induction, and the rank one case is by the definition of a pid.
 

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