-Identify the equilibrium values y'=5\sqrt{5},y>0

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The discussion centers on the differential equation \( y' = 5\sqrt{5} \) with the condition \( y > 0 \). It concludes that there are no equilibrium solutions for this equation, as \( y' \) is a constant value. The participants also touch upon the concepts of stability and the construction of a phase line, but ultimately express confusion regarding the topic and decide to move on to other subjects.

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$\textrm{ Given $y'=5\sqrt{5},y>0$ answer the following questions.}\\$
$\textrm{a. Identify the equilibrium values.}\\ $
$\textrm{Which are stable and which are unstable?}\\$
$\textrm{b. Construct a phase line. Identify the signs of $y′$ and $y′′$.}\\$
$\textrm{c. Sketch several solution curves.}\\$
ok just posting this now
have deal with it at school
basically clueless
 
Last edited:
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karush said:
$\textrm{ Given $y'=5\sqrt{5},y>0$ answer the following questions.}\\$
$\textrm{a. Identify the equilibrium values.}\\ $
$\textrm{Which are stable and which are unstable?}\\$
$\textrm{b. Construct a phase line. Identify the signs of $y′$ and $y′′$.}\\$
$\textrm{c. Sketch several solution curves.}\\$
ok just posting this now
have deal with it at school
basically clueless

Are you sure you copied the question correctly? In the given ODE, there are no equilibrium solutions, since $y'$ is a constant...(Wondering)
 
ok sorry, I will just skip this one for now..

I had to go on to another topic anyway.;););)
 

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