- #1
paulhunn
- 33
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Hi
I have been set the following problem. Z2CO3(aq)+2HCl(aq) -> 2ZCl(aq) + CO2(g) + H2o(l)
We did the experiment in class to find the amount of HCl it would take to titrate the soloution. First by measuring an amount of Z2CO3 and dissolving it into 250cm^3 of water and using methl orange indicator to know when the reaction had taken place. We did this three times using 25cm^3 samples and i got a mean titre of 26.8cm^3
We are told that it is a group one element and the concentration of the HCl is 0.1
So using the formula M=number of moles/volume in dm^3 i rearranged and got 0.1*0.0268=2.68*10^-3 meaning that it would be 2.68*10^-2 for the entire soloution.
Knowing it will take 2 moles of HCl to react one mole of substance Z it would mean there was 1.134*10^-2 moles of substance Z in the 250ml soloution and knowing the original mass that was dissolved (1.5g) i can use the formula weight(g)/number of moles=molar weight which gave me 132.275g. Then knowing that the rest of substance Z is CO3 i can subtract their weights (12+16+16+16) which gives 72.275 and then halfing to find the molar weight of Z (because in the formula we have Z2) we get 36.1375. which is relatively close to potassium.
Does my method follow correctly?
And is the 3g that i am off from potassium enough to say there was a significant error in working or is it ok?
Thanks in advance
Paul
I have been set the following problem. Z2CO3(aq)+2HCl(aq) -> 2ZCl(aq) + CO2(g) + H2o(l)
We did the experiment in class to find the amount of HCl it would take to titrate the soloution. First by measuring an amount of Z2CO3 and dissolving it into 250cm^3 of water and using methl orange indicator to know when the reaction had taken place. We did this three times using 25cm^3 samples and i got a mean titre of 26.8cm^3
We are told that it is a group one element and the concentration of the HCl is 0.1
So using the formula M=number of moles/volume in dm^3 i rearranged and got 0.1*0.0268=2.68*10^-3 meaning that it would be 2.68*10^-2 for the entire soloution.
Knowing it will take 2 moles of HCl to react one mole of substance Z it would mean there was 1.134*10^-2 moles of substance Z in the 250ml soloution and knowing the original mass that was dissolved (1.5g) i can use the formula weight(g)/number of moles=molar weight which gave me 132.275g. Then knowing that the rest of substance Z is CO3 i can subtract their weights (12+16+16+16) which gives 72.275 and then halfing to find the molar weight of Z (because in the formula we have Z2) we get 36.1375. which is relatively close to potassium.
Does my method follow correctly?
And is the 3g that i am off from potassium enough to say there was a significant error in working or is it ok?
Thanks in advance
Paul