Implicit Differentiation and coordinates

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Kar91102
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Homework Statement


Find the coordinates of the point in the first quadrant at which the tangent line to the curve x3-xy+y3=0 is parallel to the x-axis.

SO:
x= +
y= +
mtan=0

Homework Equations



[tex]\frac{dy}{dx}=m_{tan}[/tex]

The Attempt at a Solution



[tex]\frac{dy}{dx}=\frac{y-3x^{2}}{3y^{2}-x}=0[/tex]

After I get the derivative, I have no clue what to do.
 
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you have two equations two variables so solve for one of the variables
 
For the derivative to equal zero x and y must satisfy y-3x^2=0, right? But x and y must also be on the curve so x^3-xy+y^3=0. That's two equations in two unknowns. Solve them.
 
You now have two equations to solve for x and y. Oh, and here's a simplification:
a fraction is 0 only when its numerator is 0.

Blast! I walked away from the computer and Dick got in ahead of me!