Implicit Differentiation: Solving for dy/dx in (x^2-y^2)^2=(x+y)^3

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SUMMARY

The discussion focuses on the implicit differentiation of the equation (x^2 - y^2)^2 = (x + y)^3. Participants clarify that the goal is to find dy/dx as a function of x, emphasizing the need to apply the chain rule correctly to both sides of the equation. The differentiation of (x^2 - y^2)^2 requires treating y as a function of x, while (x + y)^3 also necessitates implicit differentiation. The conversation highlights the importance of understanding the distinction between finding the first derivative and the second derivative.

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  • Understanding of implicit differentiation
  • Familiarity with the chain rule in calculus
  • Knowledge of polynomial functions and their derivatives
  • Ability to manipulate algebraic expressions
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  • Practice implicit differentiation with various equations
  • Review the chain rule and its applications in calculus
  • Explore higher-order derivatives and their significance
  • Study the relationship between implicit and explicit functions
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Students studying calculus, mathematics educators, and anyone looking to deepen their understanding of implicit differentiation techniques.

Ry122
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(x^2-y^2)^2=(x+y)^3
I tried to use the chain rule on both sides but it didn't work because y needs to have the chain rule used on it explicitly and if i differentiate y explicitly then use the chain rule on everything i would be finding the 2nd derivative. So how do i differentiate this?
 
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For starters, what is the derivative with respect to x of [itex](x^2-y^2)^2[/itex]? Of [itex](x+y)^3[/itex]?
 
What does the question ask of you? That you find dy/dx as a function of x only, or simply to implicitly differentiate it?
 

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