Improper integral of x^(-p) from 0 to 1 for different values of p

[Artusartos]

Show that $$\int_0^1 x^{-p} dx = \frac{1}{1-p}$$ if 0<p<1 and $$\int_0^1 x^{-p} dx = +\inf$$ if p>1. Can anybody please give me a hint?

Thanks in advance

 

[gopher_p]

Hints: Fundamental Theorem of Calculus, Improper integrals